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n(n+1)(n+2)(n+3)+1分解因式

2020-01-30

n(n+1)(n+2)(n+3)+1分解因式

优质解答

n(n+1)(n+2)(n+3)+1
=[n(n+3)][(n+1)(n+2)]+1
=(n^2+3n)(n^2+3n+2)+1
=(n^2+3n)^2 + 2*(n^2+3n)+1
=(n^2+3n+1)^2